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0=0.005x^2-0.319x+4
We move all terms to the left:
0-(0.005x^2-0.319x+4)=0
We add all the numbers together, and all the variables
-(0.005x^2-0.319x+4)=0
We get rid of parentheses
-0.005x^2+0.319x-4=0
a = -0.005; b = 0.319; c = -4;
Δ = b2-4ac
Δ = 0.3192-4·(-0.005)·(-4)
Δ = 0.021761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.319)-\sqrt{0.021761}}{2*-0.005}=\frac{-0.319-\sqrt{0.021761}}{-0.01} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.319)+\sqrt{0.021761}}{2*-0.005}=\frac{-0.319+\sqrt{0.021761}}{-0.01} $
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